squareroots and cuberoots Model Questions & Answers, Practice Test for ssc cgl tier 1 2023
ssc cgl tier 1 2023 SYLLABUS WISE SUBJECTS MCQs
Number System
Ratio Proportion & Partnership
Averages
Percentages
Profit & Loss
Time & Work
Time & Distance
Simple Interest & Compound Interest
Mensuration: Area & Volumes
Algebraic Expressions
Linear Equations
Squareroots & Cuberoots
If $√21025$ = 145, then the value of $√210.25 + √2.1025$ = ?
Answer: (d)
$√{{210.25}/100} + √{{21025}/1000}$
⇒$145/10 + 145/100$⇒14.5 + 1.45 = 15.95
A least four digit perfect square whose first two digits and last two digits taken separately are also perfect squares, is:
Answer: (d)
$((56)^2 + (44)^2)$ ÷ ? = 16
Answer: (d)
? = ${(56)^2 + (44)^2}/16$ = $[(56)^2 + (44)^2]/(4)^2$
= $(56/4)^2 + (44/4)^2$ = $14^2 + 11^2$ = 196 + 121 = 317
The least 6 digit number which is perfect square is
Answer: (c)
Least six digit number is 100000, which is not a perfect square because it has odd number of zeroes.
First let us extract the square number hidden in it.
∴ We find that 100000 > $(316)^2$ by 154
Next square number $(317)^2$ > 100000
∴ $(316)^2$ < 100000 < $(317)^2$
∴ If we add $(317)^2$ –100000 = 489 to 100000
We get least six digit perfect sq. no.
∴ Least four digit perfect square no. is 100489.
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